a body is projected at t=0 witha velocity 10 at an angle 60 degrees with the horizontal. the radius of curvature with the trajectory at t=1 is R. neglecting the air resistance find R
Answer (1)
Student Expert
17th May, 2020
Hey!
As we know,
Vx(velocity in x direction) =10cos60 =5m/s
Vy (velocity in y direction) =10cos30 =53m/s
Velocity after t=1 second
Vx=5m/s (velocity in x direction will remain same)
Vy=(5sqrt3−10) m/s =10−5sqrt3
An=(v^2)/R
Which means
R = (Vx^2+Vy^2) /An
Which means R is (25+100+75−100sqrt3) / 10Cosθ
tanθ=(10−5sqrt3) /5
tanθ=2−sqrt3
θ=15 degrees
Then,
R=[100(2−sqrt3)] /10cos15
R =2.8m
Hope it helped to clear your delimma.
Thank you.
Comments (0)
Related Questions
Trending Articles/News
