A body is thrown such that kinetic energy and potential energy and the topmost point are equal. if the body goes to a distance of 200 m it rises to a height of?
A body is thrown such that at the topmost point of its motion, its kinetic energy and potential energy are equal. The horizontal distance it covers (range) is given as 200 meters, and we are tasked with finding the maximum height it reaches.
When a body follows a projectile motion, its total energy is distributed between kinetic energy (due to its speed) and potential energy (due to its height). At the topmost point, since kinetic energy and potential energy are equal, half of the total energy is used to reach the height, and the other half contributes to the horizontal motion.
Using the properties of projectile motion, it can be determined that the maximum height reached by the body is one-fourth of the total horizontal distance covered. Therefore, if the range is 200 meters, the height will be:
200÷4=50 meters.200 \div 4 = 50 \, \text{meters}.200÷4=50meters.
Hence, the body rises to a height of 50 meters .