a body mass 0.4 kg is whirled in a horizontal circle of radius 5 m it is performed 120 RPM the force acting on it is
Answer (1)
24th Oct, 2021
Hello Rohini,
w= 120*2*pie / 60 =4*pie rad/sec
radius=5 m , mass=0.1 kg
centripetal force=m*v^2/ r
=m*w^2*r
=32(pie)^2 newton
=315.8 N
This is the answer of the question you have asked.
Hope this helps..
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