a body of mass 2kg is moved under a n external force . its displacement is given by x(t)= 3t^2-2t+5.find the work done by the force from t=0 to t=5sec
Answer (1)
21st Dec, 2019
Hello Saksham, Greetings!
I hope that you'll be familiar with differentiation as this problem requires knowledge of the same. So, as we know:
F = Mass * Acceleration
Therefore, F = mass * d^2x/dt^2 (As, differentiation of displacement gives velocity and differentiation of velocity gives acceleration).
Therefore, F = 2 * 6 = 12N
Now, Work = F * ds = 12 ( 3 * 5^2 - 2 * 5 + 5 - ( 0 - 0 + 5)) = 780 J.
Hope this answer helps you.
Feel free to ask any more queries that trouble you.
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