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a body of mass 2kg is moved under a n external force . its displacement is given by x(t)= 3t^2-2t+5.find the work done by the force from t=0 to t=5sec


Saksham 21st Dec, 2019
Answer (1)
Haardik Dharma 21st Dec, 2019

Hello Saksham, Greetings!

I hope that you'll be familiar with differentiation as this problem requires knowledge of the same. So, as we know:

F = Mass * Acceleration

Therefore, F = mass *  d^2x/dt^2  (As, differentiation of displacement gives velocity and differentiation of velocity gives acceleration).

Therefore, F = 2 * 6 = 12N

Now, Work = F * ds = 12 ( 3 * 5^2 - 2 * 5  + 5 - ( 0 - 0 + 5)) = 780 J.

Hope this answer helps you.

Feel free to ask any more queries that trouble you.




1 Comment
Comments (1)
21st Dec, 2019
thank u sir
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