Question : A boy is late by 9 minutes if he walks to school at a speed of 4 km/hr. If he walks at the rate of 5 km/hr, he arrives 9 minutes early. The distance to his school is:
Option 1: 9 km
Option 2: 5 km
Option 3: 4 km
Option 4: 6 km
Correct Answer: 6 km
Solution :
Let $x$ km be the required distance.
According to the question,
$\frac{x}{4}-\frac{x}{5} = \frac{(9+9)}{60}$
⇒ $\frac{5x-4x}{20}= \frac{3}{10}$
$\therefore x = \frac{3}{10}×20 = 6$ km
Hence, the correct answer is 6 km.
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