Question : A boy is late by 9 minutes if he walks to school at a speed of 4 km/hr. If he walks at the rate of 5 km/hr, he arrives 9 minutes early. The distance to his school is:
Option 1: 9 km
Option 2: 5 km
Option 3: 4 km
Option 4: 6 km
Correct Answer: 6 km
Solution : Let $x$ km be the required distance. According to the question, $\frac{x}{4}-\frac{x}{5} = \frac{(9+9)}{60}$ ⇒ $\frac{5x-4x}{20}= \frac{3}{10}$ $\therefore x = \frac{3}{10}×20 = 6$ km Hence, the correct answer is 6 km.
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Question : If Abhi travels a certain distance at 6 km/hr, he reaches his destination 12 minutes early, but if he travels at 4 km/hr, he reaches his destination 10 minutes late. The speed (in km/hr) at which he should travel to reach his destination on time is _____.
Question : A man has to be at a certain place at a certain time. He finds that he shall be 20 minutes late if he walks at 3 km/hr speed and 10 minutes earlier if he walks at a speed of 4 km/hr. The distance he has to walk is:
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