Question : A bus left 60 minutes later than the scheduled time, but to reach its destination 48 km away in time, it had to increase the speed by 4 km/hr from the usual speed. What is the usual speed (in km/hr) of the bus?
Option 1: 9
Option 2: 12
Option 3: 15
Option 4: 8
Correct Answer: 12
Solution : Let the usual speed be $x$ km/hr. According to the question, $\frac{48}{x}-\frac{48}{x+4}=\frac{60}{60}$ $⇒x^2+4x-192=0$ $⇒x^2+(16-12)x-192=0$ $⇒(x+16)(x-12)=0$ Since speed cannot be negative, $\therefore x= 12$ km/hr Hence, the correct answer is 12.
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Question : A motorcyclist left $6\frac{6}{9}$ minutes later than the scheduled time but to reach its destination 21 km away on time, he had to increase his speed by 12 km/hr from the usual speed. What is the usual speed (in km/h) of the motorcyclist?
Question : A car left 3 minutes earlier than the scheduled time and to reach the destination 126 km away in time, it has to slow its speed by 6 km/hr from the usual. What is the usual speed (in km/hr) of the car?
Question : If Abhi travels a certain distance at 6 km/hr, he reaches his destination 12 minutes early, but if he travels at 4 km/hr, he reaches his destination 10 minutes late. The speed (in km/hr) at which he should travel to reach his destination on time is _____.
Question : A vehicle is going at one-fourth of its usual speed and it takes an extra 45 minutes to reach its destination. It's usual time to cover the same distance is:
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