Question : A bus starts from a bus stand after every 50 minutes in the same direction. Mohit is walking in the opposite direction at 50 km/hr. If Mohit meets each bus in 10 minutes, then what is the speed of the bus?
Option 1: 14.5 km/hr
Option 2: 15 km/hr
Option 3: 12.5 km/hr
Option 4: 10.5 km/hr
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 12.5 km/hr
Solution :
Let the speed of the bus be $x$ km/hr
According to the question,
Mohit meets each bus in 10 minutes
⇒ Distance covered by bus in (50 - 10) = 40 minutes $=$ The distance travelled by Mohit in 10 minutes
⇒ Distance covered by the bus in $\frac{40}{60}\ \mathrm{hr}$ = The distance traveled by Mohit in $\frac{10}{60}\ \mathrm{hr}$
⇒ $\frac{40x}{60} = 50 \times \frac{10}{60}$
⇒ $x = 12.5\ \mathrm{km/hr}$
Hence, the correct answer is 12.5 km/hr.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates Brochure
Your Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
Upcoming Exams
Trending Articles around SSC CHSL
