Question : A can complete 25% of a work in 10 days. B can complete 40% of the same work in 16 days. In how many days will A and B together complete twice the work mentioned above?
Option 1: 20
Option 2: 40
Option 3: 60
Option 4: 50
Correct Answer: 40
Solution :
Time taken by A to complete 25% of a work = 10 days
Time taken by A to complete the work = $10×\frac{100}{25}$ = 40 days
Part of work done by A in a day = $\frac{1}{40}$
Time taken by B to complete 40% of the same work = 16 days
Time taken by B to complete the same work = $16×\frac{100}{40}$ = 40 days
Part of work done by B in a day = $\frac{1}{40}$
Part of work done by A and B in a day = $\frac{1}{40}+\frac{1}{40}$ = $\frac{2}{40}$ = $\frac{1}{20}$
Time taken by A and B to complete the work = 20 days
Time taken by A and B to complete twice the work = 2 × 20 = 40 days
Hence, the correct answer is 40 days.
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