Question : A can do a certain work in 9 days. B is 80% more efficient than A. How many days will B and A together take to do the same work?
Option 1: $\frac{45}{14}$ Days
Option 2: $\frac{54}{13}$ Days
Option 3: $\frac{47}{14}$ Days
Option 4: $\frac{44}{13}$ Days
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Correct Answer: $\frac{45}{14}$ Days
Solution :
According to the question,
A can do a certain work in 9 days.
B is 80% more efficient than A.
So, the ratio of efficiencies of A and B = 100 : 180 = 5 : 9
Total work = Time $\times$ Efficiency
⇒ Total work = 9 $\times$ 5 = 45 units
Consider the total efficiency of A and B = 5 + 9 = 14
Total work completed by A and B together = $\frac{45}{14}$ days.
Hence, the correct answer is $\frac{45}{14}$ Days.
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