Question : A can finish a work in 20 days and B can complete the same work in 15 days. B worked for 9 days and left the job. In how many days can A alone finish the remaining work?
Option 1: 10 days
Option 2: 8 days
Option 3: 9 days
Option 4: 7 days
Correct Answer: 8 days
Solution :
Work done by A in 1 day $= \frac{1}{20}$ part of the work
Work done by B in 1 day $= \frac{1}{15}$ part of the work
So, work done by A in 9 days $= \frac{9}{15}$ part of the work
So, Remaining work = ($1-\frac{9}{15})=\frac{6}{15}$ part of the work
$\therefore$ A can do the remaining $\frac{6}{15}$ part in $(\frac{\frac{6}{15}}{\frac{1}{20}})=8$ days
Hence, the correct answer is 8 days.
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