Question : A can of water and milk mixture contains 60% milk. A part of this mixture is replaced by another mixture containing 50% milk and the percentage of milk was found to be 52%. The quantity of mixture replaced is:
Option 1: $\frac{1}{5}$
Option 2: $\frac{3}{5}$
Option 3: $\frac{4}{5}$
Option 4: $\frac{2}{5}$
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Correct Answer: $\frac{4}{5}$
Solution : Given, a can of mixture of water and milk containing 60% milk. Then, a part of this mixture is replaced by another mixture containing 50% milk. The percentage of milk is found to be 52%. ⇒ The ratio of the original solution that has 60% milk concentration to the solution that has 50% milk concentration = 2 : 8 = 1 : 4 Now, the quantity is replaced, = $1−\frac{1}{1+4}$ = $\frac{4}{5}$ Hence, the correct answer is $\frac{4}{5}$.
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