Question : A candidate who gets 20% marks in an examination, fails by 30 marks. But if he gets 32% marks, he gets 42 marks more than the minimum pass marks. Find the pass percentage of marks.
Option 1: 52%
Option 2: 20%
Option 3: 25%
Option 4: 12%
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Correct Answer: 25%
Solution : Let the maximum marks be $x$. So, the passing mark = 20% of $x$ + 30 Also, the passing mark = ($\frac{32}{100} × x) - 42$ According to the question, ($\frac{20}{100} × x)+30$ = ($\frac{32}{100} × x) - 42$ ⇒ ($\frac{12}{100} × x) = 72$ So, the maximum marks, $x$ = 600 Now, the pass marks = 20% of 600 + 30 = $\frac{20 × 600}{100}$ + 30 = 120 + 30 = 150 So, the required pass percentage of marks = $\frac{150}{600}$ × 100 = 25% Hence, the correct answer is 25%.
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