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a certain sum become 7 times itself in 9 years at SI. In how many years will it become 49 times of its initial value?


kushgupta340 18th Sep, 2021
Answer (1)
Sourav singh 18th Sep, 2021

As we know,

The formula for S.I = P*R*T/100.

And Amount = P + S.I.

Now,

Let the sum of money be 100 rupees.

In 9 years it becomes 7 times. Therefore,

100×7=700 in 9 years.

Now According to simple interest formula.

A=P(1+rt)

Where A= final amount

P= Principle amount

r= rate.

t= time

Now on putting the values and solving it we get

700=100(1+ 9r)

From this equation we get r= 0.66 or 66.66%

Now putting the values in the equation again to solve for the number of years required to get the initial amount multiplied 49 times.

4900=100(1+66.66t)

Ans t= 0.72 or 72 years

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