A certain sum of money is divided among A,B, C such that A gets half of what B and C together get.B get one third of what A andC together get.If A got 500 more than B, then how much money was divided?
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Answer (1)
10th Dec, 2019
Hello Rishabh,
It is a simple numerical of simultaneous equations.
Let, the distributions received by A, B, C be x, y, z respectively.
So, from first condition,
x = 0.5 ( y + z )
So, 2x - y - z + 0................ ( 1 )
From second condition,
y = 1/3 ( x + z )
So, x - 3y + z + 0 .................... ( 2 )
Now, from third condition, x = y + 500 ........... ( 3 )
Putting value of ( 3 ) in eqn ( 1 ), we get,
y - z = -1000
So, z = y + 1000...... ( 4 )
Now, From ( 2 ), ( 3 ) & ( 4), we get,
y = 1500/-
Putting this value in eqn ( 3 ) and ( 4 ) we get,
x = 2000/-
z = 2500/-
Hence, the amount distributed among A, B and C was 2000/-, 1500/- & 2500/- respectively.
Best Wishes.
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Comments (2)
thanks👍
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