a charge q is placed at the center of the line joining 2 equal charges Q. the system of the 3 charges will be in equilibrium of q is equal to (a) - Q/2 (b)- Q/4 (c) Q/4 (d) Q / 2
Answer (1)
13th Jun, 2020
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Given that a charge q is placed at the center C of line joining two equal charges Q each,at points A and B.
Let AB=2a
If the net force on each charge will be 0(zero) ,then the system will be in equilibrium.
let the charge Q is present at A.
At equilibrium state ,the total force on this charge is given by
1/4π e0*qQ/a^2 + 1/4π e0*qQ/2a^2 =0
=1/4π e0*qQ/a^2 = - 1/4π e0*qQ/2a^2
on solving we get,
q=-Q/4
Hope it helps!!!!
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