A circular disc is rotating about its natural access with angular velocity of 10 Radian per second a second disc of same mass is joined to e
Answer (1)
15th Jul, 2019
Hey buddy, In this question you may proceed by equating angular momentum of both side. Angular momentum in the first case is equal to angular momentum of second case.
1/2Iw^2=1/2(I1+I2)w1^2
mr^2w^2=(mr^2+m(r/2)^2)w1^2
r^2w^2=5/4r^2w1^2
4/5w^2=w1^2
4/5*100=w1^2w1=root80
Comments (0)
Related Questions
Trending Articles/News
