a circular hole of radius r/4 is made thin uniform disc having mass M and radius r as shown in the figure.The moment of inertia of the remaining portion of the disc about an axis passing through the point o and perpendicular to the plane of the disc is
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28th Oct, 2019
A circular hole of radius R/4 is made in a thin uniform disc having mass M and radius R . The moment of inertia of the remaining portion of the disc about an axis passing through the point O and perpendicular to the plane of the disc
I0=mr^2/2
1/2*m/16*r^2/16+m/16*9r^2/16(m+md)
=mr^2+18mr^2/(512)
=19mr^2/512
I remaining=mr^/2-19/512*mr^2
=237/512 mr^2
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