A committee of 5 is to be choosen from a group of 9 people. The probability that a certain couple wil either serve together or not at all is
The Total Number of all the possible ways of Selection is 9C5=126
Now if there is a certain couple which is To be Placed Together, then You can consider them One so that they will be placed Together,
Now there arise two cases.
If a couple is selected, then we need to select only 3 out of 7 that is 7C3=35
If the couple is Not selected then we need to select 5 out of 7that is 7C5=21
Therefore Probability =(35+21)/126=56/126=0.45