A concave lens of glass, refractive index 1.5, has both surfaces of the samr radius of curvature R. on immersion in a medium of refractive index 1.75, it will behave as a...
Answer (1)
20th Jun, 2020
Hello!!!
Hope you are doing great!!!
Consider refraction of light from infinity at first surface,
μ 2/v - μ 1/u = μ 2- μ 1/R
1.5/v1 - 1.75/-∞ = 1.5-1.75/-R
Consider refraction of this image from second surface
1.75/v2 - 1.5/v1 = 1.75-1.5/R
v2=3.5R
The image of light coming from infinity.
It is converging since focal length is positive.
Hope it helps!!!
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