Question : A container contains a 20 L mixture in which there is 10% sulphuric acid. Find the quantity of sulphuric acid to be added to it to make the solution contain 25% sulphuric acid.
Option 1: 2 L
Option 2: 3 L
Option 3: 4 L
Option 4: 5 L
Correct Answer: 4 L
Solution :
Initially, the quantity of sulphuric acid in the mixture is 10% of 20 L, which is 2 L.
Let the quantity of sulphuric acid be added as $x$ L.
After adding $x$ L of sulphuric acid, the total volume of the mixture becomes $(20 + x)$ L,
and the total quantity of sulphuric acid becomes $(2 + x)$ L.
The final mixture is to contain 25% sulphuric acid.
So, $\frac{{2 + x}}{{20 + x}} = \frac{25}{100}$
$\therefore x=4$
Hence, the correct answer is 4 L.
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