A coper shere of mass 2gm contains about 2*10raised to 22 atoms the charge on the nucleus of each atom is 29e . the fraction of electrons
Answer (1)
Dear Jadhav,
Since you have asked this question months ago, I hope you have solved this question.
Answering to your question, Considering you are asking about what fraction of electrons to be removed from the sphere to give it a charge of 2 microcoulomb?
According to the question, Charge on the nucleus of each atom is 29e.
therefore, Net Charge on 2gm copper sphere would be 29e * (2*10^22) = 5.8 * 10^23
Number of electrons to be removed to give 2 microcoulomb charge= q/e which would be 1.25* 10^13.
So, Fraction of electrons to be removed will be 2.16* 10^-11
Good Luck!
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