a current of two amperes corresponds to a flow of 1.25×10raise to power 18 electrons . explain?
Hi
We know that,
The current is given by
i =Q/t
Then
Q =i t
Now,Q =2×1=2C
Also,
charge Q is due to electrons, then
Q =N×e
Where,N is the number of electrons passing and e is 1.6×10−19 i.e charge on electron
Then,
N =Q/e= 2/ 1.6×10^−19
=1.25×10^19electrons
Thus , flow of 2 ampere of currents corresponds to flow of 1.25×10^19electrons electrons
Thank you