Question : A dealer sells two machines at the rate of Rs. 15000 per machine. On one he earns a profit of 20 percent and on the other, he loses 40 percent. What is his profit/loss percentage in the whole transaction?
Option 1: 20 percent loss
Option 2: 10 percent loss
Option 3: 10 percent profit
Option 4: 20 percent profit
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Correct Answer: 20 percent loss
Solution :
Let the cost price of one machine be Rs. $y$ and the other be Rs. $z$.
Cost price of 1st machine:
⇒ $y \times (1 + \frac{20}{100}) = 15000$
⇒ $y = \frac{15000}{1.2}$
⇒ $y$ = Rs. 12500
Cost price of 2nd machine:
⇒ $z \times (1 – \frac{40}{100}) = 15000$
⇒ $z = \frac{15000}{0.6}$
⇒ $z$ = 25000
⇒ Total cost price = 12500 + 25000 = Rs. 37500
⇒ Total selling price = 15000 + 15000 = Rs. 30000
⇒ Loss = 37500 – 30000 = Rs. 7500
$\therefore$ Loss percentage = 7500 $\times \frac{100}{37500}$ = 20%
Hence, the correct answer is a 20 percent loss.
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