Question : A dishonest dealer marks up his goods by 50% and then gives a discount of 20% on the marked price. Apart from this, he uses a faulty balance of 1 kg for 900 gm. What is his net profit percentage (rounded off to the nearest integer)?
Option 1: 24
Option 2: 27
Option 3: 36
Option 4: 33
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Correct Answer: 33
Solution :
Let the original cost price of the goods be Rs. 100.
He marked his goods at 50% above the cost price.
$\therefore$ The marked price of the goods = Rs. 150
He gives a discount of 20% on the marked price.
$\therefore$ Selling Price $= 150 × \frac{80}{100} = 120$
He frauds for 1 kg = 900 gm
Let assume 1 kg = 100% and 900 gm = 90%
So (100% – 90% = 10%) fraud by him.
$\therefore$ Actual cost price = 100 – (10% of 100) = Rs.90
Profit = Selling price – Cost price = 120 – 90 = Rs.30
$\therefore$ Profit percentage $= \frac{30}{90}× 100 = 33.33\% \approx 33\%$
Hence, the correct answer is 33%.
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