Question : A drink of chocolate and milk contains 8% pure chocolate by volume. If 10 litres of pure milk are added to 50 litres of this drink, the percentage of chocolate in the new drink is:
Option 1: $6 \frac{2}{3}$
Option 2: $5 \frac{2}{3}$
Option 3: $5 \frac{1}{3}$
Option 4: $6 \frac{1}{3}$
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Correct Answer: $6 \frac{2}{3}$
Solution :
A drink of chocolate and milk contains 8% pure chocolate.
10 litres of pure milk are added to 50 litres of this drink.
Let $x$ be the percentage of chocolate in the new drink.
Using the above data in the alligation method, we have:
$\frac{(x - 0)}{(8 - x)} = \frac{50}{10}$
$⇒x = 40 - 5x$
$⇒x = \frac{40}{6}$
$\therefore x = 6\frac{2}{3}\%$
Hence, the correct answer is $6\frac{2}{3}\%$.
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