A force act on 3 gM of particles in such a way that the position of particle as the function of time is given by x=3t-4tpower2+tpower3 work done during 4th second
Answer (1)
21st May, 2020
Hello!!!!
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Given ,Mass,m=3gm =0.003kg
position ,x =3t-4t^2+t^3
by differentiating x,, we get V
v=dx/dt=3-8t+3t^2
dx=(3-8t+3t^2)dt
on differentiating v ,,we get a
a=dv/dt =( -8+6t)
now ,we know that work done ,,W =∫ F.dx
dw=F.dx
dw=(ma) .dx
dw=(0.003)(-8+6t).(3-8t+3t^2)dt
dw=(0.003)(18t^3-72t^2+82t-24)dt
On integrating both sides , we get
w=(0.003) ∫0 to 4(18t^3-72t^2+82t-24)dt,
by simplifying,we get
w=0.528 J
Hope it helps!!!!
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