a force for=10N acting on a particle at an angle of 30 degrees with y-axis. find the horizontal and verticle components of force and then express force in terms of i and j
Answers (2)
Student Expert
23rd Mar, 2021
Deepika,
The solution of the query asked is given below:
As the force is making 30 degree angle with the y-axis so , for the x-component of force: Sin of 30 degree * force
= 10N Sin(30) = 5 N
X-component is 5N
For Y-component : 10*cos(30) = 8.66N
So, Fx = 5 N and Fy = 8.66N
Now, as we know: F = Xi + Yj ; where X = 5N and Y = 8.66N
Therefore, F = 5i + 8.66j
Hope it helps to clear your dilemma, thankyou!
Comments (0)
23rd Mar, 2021
Dear aspirant,
You need to resolve the force into x and y components as we see in vector. As the angle is 30 degrees with the y axis so it's j component will 10 cos 30 degree and its i component will be 10 sin 30 degree which is finally F=5√3 j + 5 I.
Comments (0)
Related Questions
Trending Articles/News
