A force of 100N applied on a block of mass 3kg as shown in fig. The coefficient of friction between the surface and block is 1/4. The friction force acting on the block is
Answer (1)
25th May, 2020
Hello!!!
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Given,
Force F=100N
mass=3kg
Coefficient of friction=μ = 1/4
As we know,F=ma
a=F/m
a=100/3 m/s^2
acceleration=100/3 m/s^2
frictional force f=μ ma
therefore f=1/4*3*100/3
f=25N
Frictional force f=25N
Hope it helps!!!!!!
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