1448 Views

A force of 100N applied on a block of mass 3kg as shown in fig. The coefficient of friction between the surface and block is 1/4. The friction force acting on the block is


prachiverma2502 23rd May, 2020
Answer (1)
Mounika Sonti 25th May, 2020

Hello!!!

Hope you are doing great!!!

Given,

Force F=100N

mass=3kg

Coefficient of friction=μ  = 1/4

As we know,F=ma

a=F/m

a=100/3 m/s^2

acceleration=100/3 m/s^2

frictional force f=μ ma

therefore f=1/4*3*100/3

f=25N

Frictional force f=25N

Hope it helps!!!!!!

Related Questions

Amity University | Journalism...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
Pearl Academy Media Programs ...
Apply
100% Placement | 500+ Recruiters | Placement support for alumni for 5 Years | Last Date to Apply: 13th Jan
MAHE Manipal Liberal Arts Adm...
Apply
Accorded Institution of Eminence by MoE, Govt. of India | NAAC A++ Grade | Ranked #4 India by NIRF 2024
Lingaya's-LLDIMS-BA-JMC 2025
Apply
NAAC A+ Grade | Partnerships with Top Recruiters
Apeejay Stya University MJMC ...
Apply
NAAC A Grade | Trans-Disciplinary Approach | Global Diversity
MAHE Media & Mass Communicati...
Apply
Accorded Institution of Eminence by MoE, Govt. of India | NAAC A++ Grade | Ranked #4 India by NIRF 2024 | 85%+ Students placed in Core Sector
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books