a gas occupying 1 litre at 80 cm pressure is expanded adiabatically to 1190cc if pressure falls to 60 cm in the process find the value of gamma
Answer (1)
5th Nov, 2020
Dear student,
For adiabetic expansion we know that - P(V^gamma) = constant.
Now, the data we have are :-
V1 = 1 litre = 1000 cc
V2 = 1190 cc
P1 = 80 cm of Hg
P2 = 60 cm of Hg.
Now,
P1 (V1)^gamma = P2 (V2)^gamma
And therefore :-
P1 / p2 = ( V2 / V1 )^gamma
4/3 = (119/100)^gamma
And now taking natural logarithm, i.e, ln on both sides we get :-
gamma( ln(119/100) ) = ln(4/3)
And on solving this equation we get :-
gamma = 1.653
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