a gaseous hydrocarbon given upon combustion, 0.72g of water and 3.08g of co2 the empirical formula of the hydrocarbon is
Answer (1)
4th Jan, 2020
Dear Anurag
I would to explain you the answer of this question
Empirical formula -
An Empirical formula represents the simplest whole number ratio of various atoms present in a compound.
General equation for combustion of hydrocarbon:
CxHy + (x+ y/4)O2 -> xCO2 + (y/2)H2O
Number of moles of CO2 produced = 3.08/44 = 0.07
Number of moles of H2O produced = 0.72/18 = 0.04
SO, x / (y/2) = 0.07/0.04 = 7/4
The formula of hydrocarbon is C7H8
I hope you understand this answer
All the best
I would to explain you the answer of this question
Empirical formula -
An Empirical formula represents the simplest whole number ratio of various atoms present in a compound.
General equation for combustion of hydrocarbon:
CxHy + (x+ y/4)O2 -> xCO2 + (y/2)H2O
Number of moles of CO2 produced = 3.08/44 = 0.07
Number of moles of H2O produced = 0.72/18 = 0.04
SO, x / (y/2) = 0.07/0.04 = 7/4
The formula of hydrocarbon is C7H8
I hope you understand this answer
All the best
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