Question : A glass jar contains 6 white, 8 black, 4 red, and 3 blue marbles. If a single marble is chosen at random from the jar, what is the probability that it is black or blue?
Option 1: $\frac{8}{21}$
Option 2: $\frac{11}{21}$
Option 3: $\frac{5}{21}$
Option 4: $\frac{1}{7}$
Correct Answer: $\frac{11}{21}$
Solution :
Given: A glass jar contains 6 white, 8 black, 4 red, and 3 blue marbles.
Number of total marbles = (6 + 8 + 4 + 3) = 21
Number of total black and blue marbles = (8 + 3) = 11
So, the probability of a chosen marble being black or blue = $\frac{11}{21}$
Hence, the correct answer is $\frac{11}{21}$.
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