a horizontal force pulls a 20kg box at a constant speed along a horizontal floor if the coefficient of friction between the box and the floor is 0.25 how much work is done by the force F in moving the box through a distance of 2moption 49j {2} 98 {3} 147 {4} 196
Answer (1)
31st Oct, 2019
Hiii Kapil answer to your question is
Since the box is moved at a constant velocity,the applied force F just overcomes the frictional force f,i.e,
F=f=μmgF=f=μmg
∴∴ Work done W=FScosθ=μmgScos0W=FScosθ=μmgScos0
⇒0.25×20×9.8×2=98J
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