Hiii Kapil answer to your question is
Since the box is moved at a constant velocity,the applied force F just overcomes the frictional force f,i.e,
F=f=μmgF=f=μmg
∴∴ Work done W=FScosθ=μmgScos0W=FScosθ=μmgScos0
⇒0.25×20×9.8×2=98J
Hope you like the answer....keep asking we are always looking for you to help....may you have a very bright future
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile