Question : A is 20% more efficient than B. If B alone can complete a piece of work in 12 days, then A alone can complete the same work in how many days?
Option 1: 10
Option 2: 12
Option 3: 14
Option 4: 16
Correct Answer: 10
Solution :
Let B be 100% efficient.
Then A will be 120% efficient.
Now, 100% efficient can do work in 12 days,
1% efficient will do work in $12 \times 100$ days.
$\therefore$ 120% efficient can do work in $\frac{12 \times 100}{120}$ = 10 days
Hence, the correct answer is 10.
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