Question : A is twice as a good worker as B and together they finish the work in 20 days. In how many days can A alone do it?
Option 1: 25 days
Option 2: 36 days
Option 3: 20 days
Option 4: 30 days
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Correct Answer: 30 days
Solution : Let the efficiency of B be $x$. ⇒ The efficiency of A is 2$x$. Total number of days needed to complete the work if A and B worked together = 20 days Total work done = Total number of days × Total efficiency = 20 × ($x$ + 2$x$) = 20 × 3$x$ = 60$x$ Number of days needed to complete the work if A worked alone = $\frac{\text{Total work}}{\text{Efficiency of A}}$ = $\frac{60x}{2x}$ = 30 days Hence, the correct answer is 30 days.
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