Question : A is twice as efficient as B and C is thrice as efficient as B. Working together, they can finish a certain work in 5 days. A and C worked together for 5 days. B alone would complete the remaining work in ____.
Option 1: 8 days
Option 2: 5 days
Option 3: 6 days
Option 4: 4 days
Correct Answer: 5 days
Solution :
Let the efficiency of B be 1 unit.
Efficiency of A = 2 × 1 = 2 units
Efficiency of C = 3 × 1 = 3 units
Total work = (1 + 2 + 3) × 5 = 30 units
Work done by A and C in 5 days = (2 + 3) × 5 = 25 units
Remaining work = 30 – 25 = 5 units
Remaining work B will complete in = $\frac{5}{1}$ = 5 days
Hence, the correct answer is 5 days.
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