Question : A is twice as efficient as B and C is thrice as efficient as B. Working together, they can finish a certain work in 5 days. A and C worked together for 5 days. B alone would complete the remaining work in ____.
Option 1: 8 days
Option 2: 5 days
Option 3: 6 days
Option 4: 4 days
Correct Answer: 5 days
Solution : Let the efficiency of B be 1 unit. Efficiency of A = 2 × 1 = 2 units Efficiency of C = 3 × 1 = 3 units Total work = (1 + 2 + 3) × 5 = 30 units Work done by A and C in 5 days = (2 + 3) × 5 = 25 units Remaining work = 30 – 25 = 5 units Remaining work B will complete in = $\frac{5}{1}$ = 5 days Hence, the correct answer is 5 days.
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Question : A can do $\frac{2}{5}$ of a work in 6 days and B can do $\frac{2}{3}$ of the same work in 12 days. A and B worked together for 6 days. C alone completed the remaining work in 8 days. A and C, working together, will complete the same work in:
Question : A can do $\frac{4}{5}$th of a work in 20 days and B can do $\frac{3}{4}$th of the same work in 15 days. They work together for 10 days. C alone completes the remaining work in 1 day. B and C together can complete $\frac{3}{4}$th of the same work in:
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