Question : A is twice as fast as B and B is thrice as fast as C. The journey covered by C in $1\frac{1}{2}$ hour will be covered by A in:
Option 1: 15 minutes
Option 2: 30 minutes
Option 3: 1 hour
Option 4: 10 minutes
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Correct Answer: 15 minutes
Solution : Given: A is twice as fast as B and B is thrice as fast as C. The journey is covered by C in $1\frac{1}{2}$ hour. Let the speed of C be $x$ metre/min. So, the speed of B will be $3x$ metre/min. And the speed of A will be $6x$ metre/min. Let the time taken by A be $y$ minutes. Here, time taken by C = $1\frac{1}{2}$ hour = $\frac{3}{2}×60 = 90$ minutes As speed is inversely proportional to time, The ratio of the speed of A and C = The ratio of the time taken by C and A ⇒ $6x:x=90:y$ ⇒ $\frac{6}{1}=\frac{90}{y}$ ⇒ $y=\frac{90}{6}=15$ minutes Hence, the correct answer is 15 minutes.
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Question : The distance between the two towns is covered in 7 hours and 30 minutes, at the speed of 72 km/hr. The time saved if the speed is increased by 25% is:
Question : The sum of three fractions A, B and C, A > B > C, is $\frac{121}{60}$. When C is divided by B, the resulting fraction is $\frac{9}{10}$, which exceeds A by $\frac{3}{20}$. What is the difference between B and C?
Question : If $\frac{a^2}{b+c}=\frac{b^2}{c+a}=\frac{c^2}{a+b}=1$, then $\frac{1}{1+a}+\frac{1}{1+b}+\frac{1}{1+c}$ is:
Question : If A : B = $\frac{1}{2}:\frac{1}{3}$, B : C = $\frac{1}{5}:\frac{1}{3}$ ,then (A + B) : (B + C) is equal to:
Question : If A : B = 2 : 5, B : C = 4 : 3, and C : D = 2 : 1, what is the value of A : C : D?
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