Question : A jar contains a mixture of milk and water, having 50% water. A part of this mixture is replaced by another mixture having 29% water. The percentage of water in the jar after replacement is 36%. What fraction of the original mixture was replaced?
Option 1: $\frac{3}{2}$
Option 2: $\frac{4}{5}$
Option 3: $\frac{1}{3}$
Option 4: $\frac{2}{3}$
Correct Answer: $\frac{2}{3}$
Solution :
Percentage of water in the first mixture = 50%
Percentage of water in the second mixture = 29%
Percentage of water in final mixture = 36%
Ratio = (36 – 29)% : (50 – 36)% = 7 :14 = 1 : 2
Total quantity = 1 + 2 = 3
Quantity replaced = 2
Required fraction = $\frac{2}{3}$
Hence, the correct answer is $\frac{2}{3}$.
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