A main shaft is running 250rpm & machine spindle is to be driven directly from the main shaft to turn at 25rpm.If the diameter of pulley fitted on machine spindle is 20cm,What would be the diameter of pulley fitted on main shaft?
Dear student, here the angular acceleration of both the shafts will be same
so, α1 = α2
=> ω1*r1 = ω2*r2
where r1 is the radius of pulley fitted on main spindle and r2 is the radius of pulley fitted on machine spindle.
=> 250*(d/2) = 25*(20/2)
=> d = 25*20/250 = 2 c.m.
Therefor diameter of the pulley to be fitted on main spindle is 2c.m.
All the best
Hope this helps
Hiii amaresh ....the answer to your question is.....
Here the angular acceleration of both the shafts will be same
so, α1 = α2
=> ω1*r1 = ω2*r2
=> 250*(d/2) = 125*(20/2)
=> d = 125*20/250 = 10cm
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