Question : A man travels for 14 hours and 40 minutes. He covers half of the journey by train at a rate of 60 km/hr and the rest by road at a rate of 50 km/hr. The distance travelled by him is:
Option 1: 720 km
Option 2: 800 km
Option 3: 960 km
Option 4: 1000 km
Correct Answer: 800 km
Solution :
Given:
A man covers half of the journey by train at a rate of 60 km/hr and the rest by road at a rate of 50 km/hr.
So, the average speed of the man = ($\frac{2×60×50}{60+50}$) = $\frac{600}{11}$ km/h
With this average speed, he travels for 14 hours and 40 minutes i.e., 14$\frac{2}{3}$ hours = $\frac{44}{3}$ hours
$\therefore$ The distance travelled by him is = ($\frac{600}{11}$×$\frac{44}{3}$) km = 800 km
Hence, the correct answer is 800 km.
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