a mass of 10kg is suspended from the free end of a spring.when set for oscillations the system executes 100 oscillations in 5minute.calculate the force constant of the spring .
Answer (1)
11th Jan, 2022
Hi reader ,
The mass of 10 kg is suspended from the free end of a string, which produces an extension of (Let x m), in the springs length from the normal position.
he spring complete 100 oscillation within 300 seconds, so the time period for one oscillation is equal to 3 seconds. So, the angular frequency is equal to 2π/3 Hz.
Time period= 2π×√m/k, where m = 10kg and Time=3 second. So, the value of k= 44.4
Hope it helps!!
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