38 Views

a merry go round has a mass of 1640kg and a radius of7.50m.how much net work is required to accelerate it from rest to a rotation rate of 1 revolution per 8 second


Annu 27th Sep, 2020
Answer (1)
Ayush 10th Nov, 2020

Hi Candidate,

The force in the Merry- Go Round is produced as a result of Centripetal acceleration acting on the body (Merry-go-round) which helps the body to move in a circular motion.

The formula for Centripetal Force is given by mass multiplied by Centripetal acceleration. So, the Centripetal force= m*w*w*r.

Here mass= 1640kg, Radius= 7.50m, Rotational velocity (w)= 8 rev. per second.                                    Force= 1640*8*8*7.50= 787.2 KNewton.

Hope that this answer helps you!!

Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Amity University Noida MBA Ad...
Apply
Amongst top 3% universities globally (QS Rankings)
DES University B.Tech Admissi...
Apply
Last Date to Apply: 30th April'25. Ranked 10th among Emerging Engineering Institutes in India by Times
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
UPES B.Tech Admissions 2025
Apply
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 28th April
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books