a monoatomic ideal gas of volume 1 litre and pressure 8 atmosphere undergoes adiabatic expansion until the pressure drops to 1atmosphere .what is the volume and how much work is done
Hello Sejal,
According to the formula
P1(V1)^r= P2(V2)^r
You can easily calculate the answer,
As P1=8atm
P2=1 atm
V1=1ltr
So V2= (8)^2/3
While work done will be 810.4 J.
I hope it helps,
Best of luck