A number is chosen randomly from numbers 1 to 60.The probability that the chosen number is a multiple of 2 or 5 is.?
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Let us suppose A:Number is multiple of 2.
Let us suppose B:number is multiple of 5.
Then, n(A)=30
n(B)=12
n(A intersection B)=6
=> P(A or B)=P(A)+P(B)-P(A and B)
=> P(A or B)= 30/60 + 12/60 -6/60
=> P(A or B)=36/60
=> P(A or B)= 3/5 ans.
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