Question : A number, when divided by 15 and 18 every time, leaves 3 as a remainder, the least possible number is:
Option 1: 83
Option 2: 103
Option 3: 39
Option 4: 93
Correct Answer: 93
Solution : Given, A number, when divided by 15 and 18 every time, leaves 3 as a remainder. LCM of 15 and 18 = 2 × 3 × 3 × 5 = 90 It leaves 3 as a remainder in each case So, the required least number = 90 + 3 = 93 Hence, the correct answer is 93.
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Question : The least number, which when divided by 5, 6, 7 and 8 leaves a remainder of 3, but when divided by 9, leaves no remainder, is:
Question : What is the least number which when divided by 15, 18 and 36 leaves the same remainder 9 in each case and is divisible by 11?
Question : Find the least number which when divided by 4, 9, 12, and 15, leaves the remainder 3 in each case.
Question : What is the sum of the digits of the least number which when divided by 15,18, and 36 leaves the same remainder 9 in each case and is divisible by 11?
Question : A number, when divided by 729, gives a remainder of 56. What will we get as a remainder if the same number is divided by 27?
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