a parallel plate condenser has two circular metal plates of radius 10cm at adistance the condenser being charged with electric field at rate5* 10000000000000 the displacement current
Answer (1)
11th Jun, 2020
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Radius of circular plate=r=2cm=0.02m
distance between the plates=d=0.1mm=0.1*10^-3m
the change in potential difference between the plates dV/dt=5*10^13vs
Permitivity of free space=eo=8.85*10^-12 C^2N^-1m^-2
Hence area of the each plate,A=πr^2
=π (0.02)^2
=1.26*10^-3 m^2--------------------1
we know,C=eoA/d
C=8.85*10^-12*1.26*10^-3/0.1*10^-3
C=11.15*10^-11 F
displacement current=Id=C.dV/dt
Id=11.15*10^-11*5*10^13
Id=57.55*10^2 A
Hope it helps!!!!
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